通过Rust实现基于TCP的简单网络传输

这个示例演示了如何使用Rust（版本号：1.51.0）实现基于TCP的简单网络传输。它包括客户端和服务器端代码，可以用于建立基于TCP的通信过程。客户端将发送一个字符串给服务器端，服务器端将对字符串进行转换并将其发送回客户端。

// 客户端代码
use std::io::{BufRead,BufReader,Write};
use std::net::TcpStream;

fn main() -> std::io::Result<()> {
    let mut stream = TcpStream::connect("127.0.0.1:8080")?;
    let message = "Hello from client!";
    stream.write_all(message.as_bytes())?;
    let mut reader = BufReader::new(&stream);
    let mut buffer = String::new();
    reader.read_line(&mut buffer)?;
    println!("Received message: {}", buffer.trim());
    Ok(())
}

// 服务器端代码
use std::io::{BufRead,BufReader,Write};
use std::net::{TcpListener,TcpStream};

fn handle_client(stream: TcpStream) -> std::io::Result<()> {
    let mut reader = BufReader::new(&stream);
    let mut buffer = String::new();
    reader.read_line(&mut buffer)?;
    println!("Received message: {}", buffer.trim());
    let mut response = String::from("Server says: ");
    response.push_str(&buffer.trim());
    stream.write_all(response.as_bytes())?;
    Ok(())
}

fn main() -> std::io::Result<()> {
    let listener = TcpListener::bind("127.0.0.1:8080")?;
    for stream in listener.incoming() {
        handle_client(stream?)?;
    }
    Ok(())
}

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